Jawaban dari "The normal boiling point of water is 100.0 °C, and the heat of vaporization is ΔHvap = 40.7 kJ/mol...."

Jawaban dari "The normal boiling point of water is 100.0 °C, and the heat of vaporization is ΔHvap = 40.7 kJ/mol...."

Jika anda sedang mencari jawaban atas pertanyaan The normal boiling point of water is 100.0 °C, and the heat of vaporization is ΔHvap = 40.7 kJ/mol. What is the boiling point of water in °C on top of Pikes Peak in Colorado, where P = 407 mm Hg? ente berada di website yang tepat. Kami ada 1 jawaban mengenai The normal boiling point of water is 100.0 °C, and the heat of vaporization is ΔHvap = 40.7 kJ/mol. What is the boiling point of water in °C on top of Pikes Peak in Colorado, where P = 407 mm Hg?. Silakan lihat jawaban lebih lanjut di bawah:

Jawaban: #1:

Tekanan Uap, Temperatur awal dan Temperatur Akhir dalam persoalan Kimia

Penjelasan:

Diketahui :

T1 = 100°C

dirubah menjadi satuan Kelvin = 373 K

ΔHvap = 40.7 KJ/mol

diubah menjadi satuan J/mol = 40700 J/mol

P = 407 mmHg

diubah menjadi satuan atm = 0,5355 atm

R = 8,314 J/mol.K

nilai ketetapan

Ditanya : T2....?

Penyelesaian :

[tex]ln (\frac1P2) = (\fracHvapR ) (\frac1T2 - \frac1T1 )[/tex]

[tex]ln (\frac10,5355) = (\frac407008,314 ) (\frac1T2 - \frac1373 )\\[/tex]

ln 1,8674 = 4895,35 [tex](\frac1T2 - \frac1373)[/tex]

0,62455 = [tex](\frac4895,35T2 - \frac4895,35373)[/tex]

0,62455 = [tex]\frac4895,35T2[/tex] - 13,124

[tex]\frac4895,35T2[/tex] = 0,62455 + 13,124

[tex]\frac4895,35T2[/tex] = 13,7488

T2 = [tex]\frac4895,3513,7488[/tex]

T2 = 356,056 K

Dari perhitungan diatas didapatkan nilai dari temperatur water atauT2 on top of pikes peak in Colorado sebesar 356,056 K atau sama dengan 83°C

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